Last updated at Sept. 11, 2020 by Teachoo
Transcript
Multiply 2√15 by 7√5 2√15 × 7√5 = 2 × 7 ×√15 × √5 = 14 ×√(3 × 5) × √5 = 14 ×√3 × √5 × √5 = 14 ×√3 × 5 = 𝟕𝟎√𝟑
Rationalising
Add (3√2+7√3) and (√2−5√3)
Divide 5√11 by 3√33
Multiply 2√15 by 7√5 You are here
Simplify (√5+√7)^2
Simplify (√4−√13)(√4+√13)
Simplify (9−√3)(9+√3)
Simplify (3√5−5√2)(4√5+3√2)
Rationalise the denominator of 8/√7
Rationalise the denominator of 1/((8 + 5√2))
Simplify (7√3)/(√10 + √3)−(2√5)/(√6 + √5)−(3√2)/(√15 + 3√2)
Multiple Choice Questions - Chapter 1 Class 9 Maths
Example 17
If a and b are rational numbers and (√11 − √7)/(√11 + √7) = a – b√77, find the value of a and b
Example 18
Find the values of a and b if (7 + 3√5)/(3 + √5) – (7 − 3√5)/(3 − √5) = a+√5 b
If x = 1/(2 − √3), find the value of x^3 − 2x^2 − 7x + 5
Ex 1.5, 5 (i)
If a = 5 + 2√6 and b = 1/a, then what will be the value of a^2+b^2 ?
Example 19
Example 20 Important
Rationalising
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